(2x^2+x-7)/(x-5)

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Solution for (2x^2+x-7)/(x-5) equation: 


D( x )

x-5 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x in (-oo:5) U (5:+oo)

(2*x^2+x-7)/(x-5) = 0

2*x^2+x-7 = 0

2*x^2+x-7 = 0

DELTA = 1^2-(-7*2*4)

DELTA = 57

DELTA > 0

x = (57^(1/2)-1)/(2*2) or x = (-57^(1/2)-1)/(2*2)

x = (57^(1/2)-1)/4 or x = (-(57^(1/2)+1))/4

(x+(57^(1/2)+1)/4)*(x-((57^(1/2)-1)/4)) = 0

((x+(57^(1/2)+1)/4)*(x-((57^(1/2)-1)/4)))/(x-5) = 0

( x+(57^(1/2)+1)/4 )

x+(57^(1/2)+1)/4 = 0 // - (57^(1/2)+1)/4

x = -((57^(1/2)+1)/4)

( x-((57^(1/2)-1)/4) )

x-((57^(1/2)-1)/4) = 0 // + (57^(1/2)-1)/4

x = (57^(1/2)-1)/4

x in { -((57^(1/2)+1)/4), (57^(1/2)-1)/4 }

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